Zizou Bergs and Jan-Lennard Struff to meet in Indian Wells 1st round

The two players will face off for the second time in their careers on Wednesday at the BNP Paribas Open

Published on Mar. 4, 2026

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Zizou Bergs and Jan-Lennard Struff are set to square off in the first round of the BNP Paribas Open in Indian Wells on Wednesday. This will be the second career meeting between the two players, with Struff holding a 1-0 head-to-head advantage after winning their previous matchup in Davis Cup in 2022. Bergs is currently ranked 47th in the world, while Struff is ranked 80th.

Why it matters

This first-round matchup at the prestigious Indian Wells tournament will be an early test for both players as they look to make a deep run in the event. Bergs is seeking to build on his semifinal appearance in Australia earlier this year, while Struff will be aiming to recapture the form that saw him reach a career-high ranking of 21 in 2019.

The details

Bergs and Struff have never faced each other on hard courts, with their only previous meeting coming on clay in Davis Cup in 2022, where Struff prevailed 6-4, 7-6(9). Bergs has a 4-4 record on hard courts in 2026, while Struff is 4-5. Both players are coming off first-round losses in their most recent tournament in Dubai.

  • The match is scheduled for Wednesday, March 4, 2026 at 1:00 PM local time.

The players

Zizou Bergs

A 47th-ranked Belgian player who reached the semifinals in Australia earlier this year.

Jan-Lennard Struff

An 80th-ranked German player who reached a career-high ranking of 21 in 2019.

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The takeaway

This first-round matchup at Indian Wells will be an intriguing clash between two players looking to make their mark on the ATP Tour. Bergs will be aiming to continue his strong start to the season, while Struff will be hoping to rediscover the form that saw him reach the fourth round at this event in 2019.